388. Longest Absolute File Path
package LeetCode_388 import java.util.* /** * 388. Longest Absolute File Path * https://leetcode.com/problems/longest-absolute-file-path/description/ * * We will represent the file system as a string where "\n\t" mean a subdirectory of the main directory, * "\n\t\t" means a subdirectory of the subdirectory of the main directory and so on. * Each folder will be represented as a string of letters and/or digits. * Each file will be in the form "s1.s2" where s1 and s2 are strings of letters and/or digits. For example, the file system above is represented as "dir\n\tsubdir1\n\t\tfile1.ext\n\t\tsubsubdir1\n\tsubdir2\n\t\tsubsubdir2\n\t\t\tfile2.ext". Given a string input representing the file system in the explained format, return the length of the longest absolute path to a file in the abstracted file system. If there is no file in the system, return 0. Constraints: 1. 1 <= input.length <= 104 2. input may contain lower-case or upper-case English letters, a new line character '\n', a tab character '\t', a dot '.', a space ' ' or digits. * */ class Solution { /* * solution: Stack, save all the length of candidate in stack, Time complexity:O(n), Space complexity:O(n) * */ fun lengthLongestPath(input: String): Int { var result = 0 //save all the length val stack = Stack<Int>() val stringList = input.split("\n") for (path in stringList) { //last index of \t is current line's level val level = path.lastIndexOf("\t") + 1 //try to find its parent, when stack size == level, the pop one is parent while (stack.size > level) { stack.pop() } val parent = if (stack.isEmpty()) 0 else stack.peek() + 1 //push a new candidate val newLen = parent + path.length - level stack.push(newLen) //if is file if (path.contains(".")) { result = Math.max(result, newLen) } } return result } }