398. Random Pick Index
package LeetCode_398 /** * 398. Random Pick Index * https://leetcode.com/problems/random-pick-index/description/ * * Given an array of integers with possible duplicates, randomly output the index of a given target number. * You can assume that the given target number must exist in the array. Note: The array size can be very large. Solution that uses too much extra space will not pass the judge. Example: int[] nums = new int[] {1,2,3,3,3}; Solution solution = new Solution(nums); // pick(3) should return either index 2, 3, or 4 randomly. Each index should have equal probability of returning. solution.pick(3); // pick(1) should return 0. Since in the array only nums[0] is equal to 1. solution.pick(1); * */ class Solution(nums: IntArray) { /* for example input: {1,2,3,3,3} * return Iterable of IndexedValue with value,index like this: * 1=[0],2=[1],3=[2, 3, 4], then get random in values * */ private val numWithIndex = nums.withIndex().groupBy({it.value},{it.index}) fun pick(target: Int): Int { return numWithIndex[target]?.random()?: error("$target not found") } } /** * Your Solution object will be instantiated and called as such: * var obj = Solution(nums) * var param_1 = obj.pick(target) */
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