207. Course Schedule

复制代码
package LeetCode_207

import java.util.*
import kotlin.collections.ArrayList

/**
 * 207. Course Schedule
 * https://leetcode.com/problems/course-schedule/description/
 *
There are a total of numCourses courses you have to take, labeled from 0 to numCourses-1.
Some courses may have prerequisites, for example to take course 0 you have to first take course 1,which is expressed as a pair: [0,1]
Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.

Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should
also have finished course 1. So it is impossible.
 * */
class Solution {
    /**
     * solution: BFS
     * Time complexity:O(n^2), Space complexity:O(n)
     * */
    fun canFinish(numCourses: Int, prerequisites: Array<IntArray>): Boolean {
        val graph = ArrayList<ArrayList<Int>>()
        //create graph by prerequisites
        for (i in 0 until numCourses) {
            graph.add(ArrayList())
        }
        for (item in prerequisites){
            val start = item[1]
            val end = item[0]
            graph[start].add(end)
        }

        //calculate in degree
        val indegrees = IntArray(numCourses)
        for (g in graph){
            for (item in g){
                indegrees[item]++
            }
        }

        val queue = LinkedList<Int>()
        for (i in 0 until numCourses) {
            if (indegrees[i]==0){
                queue.offer(i)
            }
        }

        while (queue.isNotEmpty()){
            val cur = queue.poll()
            for (item in graph[cur]){
                indegrees[item]--
                if (indegrees[item]==0){
                    queue.offer(item)
                }
            }
        }

        for (i in 0 until numCourses){
            if (indegrees[i]!=0){
                //represent graph got a cycle, so return false
                return false
            }
        }

        return true
    }
}
复制代码

 

posted @   johnny_zhao  阅读(142)  评论(0编辑  收藏  举报
编辑推荐:
· AI与.NET技术实操系列(二):开始使用ML.NET
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
阅读排行:
· DeepSeek 开源周回顾「GitHub 热点速览」
· 物流快递公司核心技术能力-地址解析分单基础技术分享
· .NET 10首个预览版发布:重大改进与新特性概览!
· AI与.NET技术实操系列(二):开始使用ML.NET
· .NET10 - 预览版1新功能体验(一)
历史上的今天:
2019-06-30 Daily Coding Problem: Problem #315
点击右上角即可分享
微信分享提示