
/**
* 112. Path Sum
* https://leetcode.com/problems/path-sum/description/
*
* Given a binary tree and a sum,
* determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Note: A leaf is a node with no children.
Example:
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
* */
import java.util.*
class Solution {
fun hasPathSum(root_: TreeNode?, sum: Int): Boolean {
//preorder, root->left->right
var root = root_
val stack = Stack<TreeNode>()
stack.push(root)
while (!stack.isEmpty()){
root = stack.pop()
if (root==null){
continue
}
if (root.left==null && root.right==null){
//node is leaf
if (root.`val`==sum){
return true
}
}
//child's val add up with it parent's val
if (root.left!=null){
root.left.`val`+=root.`val`
stack.push(root.left)
}
if (root.right!=null){
root.right.`val`+=root.`val`
stack.push(root.right)
}
}
return false
}
}

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