66. Plus One

/**
* 66. Plus One
* https://leetcode.com/problems/plus-one/description/
* https://www.cnblogs.com/grandyang/p/4079357.html
*
* Given a non-empty array of digits representing a non-negative integer, plus one to the integer.

The digits are stored such that the most significant digit is at the head of the list,
and each element in the array contain a single digit.

You may assume the integer does not contain any leading zero, except the number 0 itself.

Example 1:

Input: [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.

Example 2:

Input: [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
* */
复制代码
class Solution {
    fun plusOne(digits: IntArray): IntArray {
        val n = digits.size;
        for (i in (n - 1) downTo 0) {
            if (digits[i] < 9) {
                ++digits[i];
                return digits;
            }
            digits[i]=0//把该位的9变成0
        }
        //处理尾数为9的情况
        var result = IntArray(n + 1);
        result[0] = 1;
        return result;
    }
}
复制代码

 

posted @   johnny_zhao  阅读(169)  评论(0编辑  收藏  举报
编辑推荐:
· AI与.NET技术实操系列(二):开始使用ML.NET
· 记一次.NET内存居高不下排查解决与启示
· 探究高空视频全景AR技术的实现原理
· 理解Rust引用及其生命周期标识(上)
· 浏览器原生「磁吸」效果!Anchor Positioning 锚点定位神器解析
阅读排行:
· DeepSeek 开源周回顾「GitHub 热点速览」
· 物流快递公司核心技术能力-地址解析分单基础技术分享
· .NET 10首个预览版发布:重大改进与新特性概览!
· AI与.NET技术实操系列(二):开始使用ML.NET
· .NET10 - 预览版1新功能体验(一)
点击右上角即可分享
微信分享提示