Java 8 实现各种List操作
利用java8新特性,可以用简洁高效的代码来实现一些数据处理。
定义1个Apple对象:
public class Apple {
private Integer id;
private String name;
private BigDecimal money;
private Integer num;
public Apple(Integer id, String name, BigDecimal money, Integer num) {
this.id = id;
this.name = name;
this.money = money;
this.num = num;
}
}
添加一些测试数据:
Apple apple1 = new Apple(1,"苹果1",new BigDecimal("3.25"),10);
Apple apple2 = new Apple(1,"苹果2",new BigDecimal("1.35"),20);
Apple apple3 = new Apple(2,"香蕉",new BigDecimal("2.89"),30);
Apple apple4 = new Apple(3,"荔枝",new BigDecimal("9.99"),40);
List<Apple> appleList = Lists.newArrayList(apple1, apple2, apple3, apple4);
1、分组
List里面的对象元素,以某个属性来分组,例如,以id分组,将id相同的放在一起:
//List 以ID分组 Map<Integer,List<Apple>>
Map<Integer, List<Apple>> groupBy = appleList.stream().collect(Collectors.groupingBy(Apple::getId));
2、List转Map
id为key,apple对象为value,可以这么做:
/**
* List -> Map
* 需要注意的是:
* toMap 如果集合对象有重复的key,会报错Duplicate key ....
* apple1,apple12的id都为1。
* 可以用 (k1,k2)->k1 来设置,如果有重复的key,则保留key1,舍弃key2
*/
Map<Integer, Apple> appleMap = appleList.stream().collect(Collectors.toMap(Apple::getId, a -> a,(k1,k2)->k1));
3、过滤Filter
从集合中过滤出来符合条件的元素:
//过滤出符合条件的数据
List<Apple> filterList = appleList.stream().filter(a -> a.getName().equals("香蕉")).collect(Collectors.toList());
4.求和
将集合中的数据按照某个属性求和:
//计算 总金额
BigDecimal totalMoney = appleList.stream().map(Apple::getMoney).reduce(BigDecimal.ZERO, BigDecimal::add);
5.查找流中最大 最小值
Collectors.maxBy 和 Collectors.minBy 来计算流中的最大或最小值。
Optional<Dish> maxDish = Dish.menu.stream().
collect(Collectors.maxBy(Comparator.comparing(Dish::getCalories)));
maxDish.ifPresent(System.out::println);
Optional<Dish> minDish = Dish.menu.stream().
collect(Collectors.minBy(Comparator.comparing(Dish::getCalories)));
minDish.ifPresent(System.out::println);
6.去重
// 根据id去重
List<Person> unique = appleList.stream().collect(
collectingAndThen(toCollection(() -> new TreeSet<>(comparingLong(Apple::getId))), ArrayList::new)
);