结对作业
项目合作者：余廷锋3118005026 罗欢3118005014
1、githut地址：https://github.com/xiaojok/work2.git
2、psp表格
|
PSP2.1 |
Personal Software Process Stages |
预估耗时（分钟） |
实际耗时（分钟） |
|
Planning |
计划 |
30 |
20 |
|
· Estimate |
· 估计这个任务需要多少时间 |
30 |
20 |
|
Development |
开发 |
980 |
710 |
|
· Analysis |
· 需求分析 (包括学习新技术) |
50 |
30 |
|
· Design Spec |
· 生成设计文档 |
30 |
20 |
|
· Design Review |
· 设计复审 (和同事审核设计文档) |
30 |
10 |
|
· Coding Standard |
· 代码规范 (为目前的开发制定合适的规范) |
100 |
30 |
|
· Design |
具体设计 |
50 |
100 |
|
· Coding |
· 具体编码 |
500 |
450 |
|
· Code Review |
· 代码复审 |
50 |
10 |
|
· Test |
· 测试（自我测试，修改代码，提交修改） |
30 |
10 |
|
Reporting |
报告 |
50 |
20 |
|
· Test Report |
· 测试报告 |
10 |
10 |
|
· Size Measurement |
· 计算工作量 |
10 |
10 |
|
· Postmortem & Process Improvement Plan |
· 事后总结, 并提出过程改进计划 |
10 |
10 |
|
合计 |
|
980 |
710 |
3、设计实现过程：在设计过程中，主要是通过把每种可能的情况列出来，比如只有一个操作符的时候就把四个操作符列出来，有两个的时候就把16种情况列出来，然后再进行分类解决操作。最后设计出计算正确和错误的题数。
4、代码：
#include<stdio.h> #include <stdlib.h> #include <time.h> #include <iostream> using namespace std; int numb1,numb2,numb3,i; //随机生成的数值 int op1,op2; //运算符 FILE *fp; //指向答案文件 FILE *fb; //指向题目文件 //辗转相除法 int gcd(int numb1,int numb2) { if(numb2==0) return numb1; return gcd(numb2,numb1%numb2); } int caseone(int numb1,int numb2,int max,int i) { int gcd(int numb1,int numb2); int temp; //中间值 int result; op1=rand()%4+1; //op1的生成值为1到4，分别对应加法，减法，乘法，除法 fb=fopen("Exercises.txt","a"); fp=fopen("Answers.txt","a"); //打开文件 switch(op1){ case 1: //op1为1的时候，执行加法操作 result=numb1+numb2; fprintf(fp,"%d.答案=%d\n",i,result); //写入文件 fclose(fp); //关闭文件 fprintf(fb,"%d.%d+%d=%d\n",i,numb1,numb2,result); fclose(fb); break; case 2 : //op1为2的时候，执行减法操作； if(numb1<numb2) //为保证结果不为零，当出现生成的被减数比减数小，进行两者值的交换 { temp=numb1; numb2=numb1; numb1=temp; } result=numb1-numb2; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d-%d =%d\n",i,numb1,numb2,result); fclose(fb); break; case 3 : //op1为3的时候，执行乘法操作； result=numb1*numb2; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d*%d =%d\n",i,numb1,numb2,result); fclose(fb); break; case 4 : //op1为4的时候，执行除法操作； if(numb2==0) numb2=rand()%max+1; temp=gcd(numb1,numb2); fprintf(fp,"%d.答案=%d/%d\n",i,numb1/temp,numb2/temp); fclose(fp); fprintf(fb,"%d.%d/%d =%d/%d\n",i,numb1,numb2,numb1/temp,numb2/temp); fclose(fb); break; default:printf("ERROR\n"); } return 0; } int casetwo(int numb1,int numb2,int numb3,int max,int i) { int gcd(int numb1,int numb2); int result, result1,temp,temp1; op1=rand()%4+1; op2=rand()%4+1; //op1,op2的生成值为1到4，分别对应加法，减法，乘法，除法 fp=fopen("Answers.txt","a"); fb=fopen("Exercises.txt","a"); switch(op1){ case 1 : switch(op2){ case 1 : //op1,op2均为加法的情况 result1=numb1+numb2; result=result1+numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d+%d+%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 2 : //op1为加法,op2为减法的情况 result1=numb1+numb2; if(result1<numb3) { temp=numb3; numb3=numb2; numb2=temp; } result=numb1+numb2-numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d+%d-%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 3 : //op1为加法,op2为乘法的情况 result1=numb2*numb3; result=numb1+result1; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d+%d*%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 4 : //op1为加法,op2为除法的情况 if(numb3==0) { numb3=rand()%max+1; } temp=gcd(numb2,numb3); fprintf(fp,"%d.答案=%d'%d/%d\n",i,numb1,numb2/temp,numb3/temp); fclose(fp); fprintf(fb,"%d.%d+%d/%d%=%d'%d/%d\n",i,numb1,numb2,numb3,numb1,numb2/temp,numb3/temp); fclose(fb); break; default:printf("ERROR\n"); } break; case 2 : switch(op2){ case 1 : //op1为减法,op2为加法的情况 if(numb1<numb2) //为保证结果不为零，当出现生成的被减数比减数小，进行两者值的交换 { temp=numb1; numb2=numb1; numb1=temp; } result=numb1-numb2+numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d-%d+%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 2 : //op1为减法,op2为减法的情况 do{ numb1=rand()%max; numb2=rand()%max; numb3=rand()%max; }while((numb1-numb2-numb3)<=0); result=numb1-numb2-numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d-%d-%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 3 : //op1为减法,op2为乘法的情况 do{ numb1=rand()%max; numb2=rand()%max; numb3=rand()%max; }while((numb1-numb2*numb3)<0); result=numb1-numb2*numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d-%d*%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 4 : //op1为减法,op2为除法的情况 do{ numb1=rand()%max; numb2=rand()%max; numb3=rand()%max; }while((numb1-numb2/numb3)<0||numb3==0); result=numb1-numb2/numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d-%d/%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; default:printf("ERROR\n"); } break; case 3 : switch(op2){ case 1 : //op1为乘法,op2为加法的情况 result=numb1*numb2+numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d*%d+%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 2 : //op1为乘法,op2为减法的情况 do{ numb1=rand()%max; numb2=rand()%max; numb3=rand()%max; }while((numb1*numb2-numb3)<0); result=numb1*numb2-numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d*%d-%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 3 : //op1为乘法,op2为乘法的情况 result=numb1*numb2*numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d*%d*%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 4 : //op1为乘法,op2为除法的情况 do{ numb3=rand()%max; }while(numb3==0); temp1=numb1*numb2; temp=gcd(temp1,numb3); fprintf(fp,"%d.答案=%d/%d\n",i,temp1/temp,numb3/temp); fclose(fp); fprintf(fb,"%d.%d*%d/%d%=%d/%d\n",i,numb1,numb2,numb3,temp1/temp,numb3/temp); fclose(fb); break; default:printf("ERROR\n"); } break; case 4 : switch(op2){ case 1 : //op1为除法,op2为加法的情况 do{ numb2=rand()%max; }while(numb2==0); temp=gcd(numb1,numb2); fprintf(fp,"%d.答案=%d'%d/%d\n",i,numb3,numb1/temp,numb2/temp); fclose(fp); fprintf(fb,"%d.%d/%d+%d%=%d'%d/%d\n",i,numb1,numb2,numb3,numb3,numb1/temp,numb2/temp); fclose(fb); break; case 2 : //op1为除法,op2为减法的情况 do{ numb3=rand()%max; }while( (numb1/numb2-numb3)<0||numb2==0); result=numb1/numb2-numb3; fprintf(fp,"%d.答案=%d\n",i,result); fclose(fp); fprintf(fb,"%d.%d/%d-%d%=%d\n",i,numb1,numb2,numb3,result); fclose(fb); break; case 3 : //op1为除法,op2为乘法的情况 do{ numb2=rand()%max; }while(numb2==0); temp1=numb1*numb3; temp=gcd(temp1,numb2); result=numb1/numb2*numb3; fprintf(fp,"%d.答案=%d/%d\n",i,temp1/temp,numb2/temp); fclose(fp); fprintf(fb,"%d.%d/%d*%d%=%d/%d\n",i,numb1,numb2,numb3,temp1/temp,numb2/temp); fclose(fb); break; case 4 : //op1为除法,op2为除法的情况 do{ numb2=rand()%max; numb3=rand()%max; }while(numb3==0||numb2==0); result=numb1/numb2/numb3; temp1=numb2*numb3; temp=gcd(temp1,numb1); fprintf(fp,"%d.答案=%d/%d\n",i,numb1/temp,temp1/temp); fclose(fp); fprintf(fb,"%d.%d/%d/%d%=%d/%d\n",i,numb1,numb2,numb3,numb1/temp,temp1/temp); fclose(fb); break; default:printf("ERROR\n"); } break; default:printf("ERROR\n"); } fclose(fp); fclose(fb); return 0; } /*计算的题目数量*/ int Count(char file[]) { FILE *fp1; char a; int x=0; if((fp1=fopen(file,"r"))==NULL) { printf("read file failed！\n"); exit(0); } while(!feof(fp1)) { a=fgetc(fp1); if(a=='\n') x++; } fclose(fp1); return x; } /* 答案判断对错函数*/ void Put_Judge(char *str1,char *str2,int n) { int i,j; FILE *out; out=fopen("Grade.txt","w"); for(i=0,j=0;i<n;i++) /*对的个数*/ if(*(str1+i)==*(str2+i)) j++; fprintf(out,"Correct:%d (",j); for(i=0;i<n;i++) { /*对的序号*/ if(*(str1+i)==*(str2+i)) fprintf(out," %d ",(i+1)); } fprintf(out,")\n"); fprintf(out,"Wrong:%d (",(n-j)); for(i=0;i<n;i++) { /*错的序号*/ if(*(str1+i)!=*(str2+i)) fprintf(out," %d ",(i+1)); } fprintf(out,")\n"); fclose(out); printf("OK"); } /*读取学生答案的函数*/ void GetAnswers(char infile[],char *str) { FILE *in; char a; int i=0; if((in=fopen(infile,"r"))==NULL) { printf("read file failed！\n"); exit(0); } while(!feof(in)) { *(str+i)=0; a=fgetc(in); if(a!='=') continue; while(1) { a=fgetc(in); if(a=='\n')break; *(str+i)*=10; *(str+i)+=(a-48); } printf("%d ",*(str+i)); i++; } printf("\n"); fclose(in); } int main() { int subnumber,max int opnum; int caseone(int numb1,int numb2,int max,int i); //函数的声明 int casetwo(int numb1,int numb2,int numb3,int max,int i); FILE *fp; fp=fopen("Exercises.txt","w"); fb=fopen("Answers.txt","w"); //建立文件 fclose(fp); fclose(fb); srand((unsigned)time(0)); //为保证每次运行程序的时候生成的题目都不一样 printf("***************随机生成四则运算题目*****************************\n"); printf("1.使用 -n 参数控制生成题目的个数\n"); printf("2.使用 -r 参数控制题目中数值（自然数、真分数和真分数分母）的范围\n"); printf("请输入n："); scanf("%d",&subnumber); printf("请输入r："); scanf("%d",&max); printf("题目生成中，请稍后...\n"); for(i=1;i<=subnumber;i++) { //for循环生成题目 opnum=rand()%2+1; switch(opnum) { case 1 : //当随机数是生成1个运算符时 numb1=rand()%max; numb2=rand()%max; caseone(numb1,numb2,max,i); //执行函数的同时得同时执行把表达式输出到txt文件中 break; case 2 : //当随机数是生成2个运算符时 numb1=rand()%max; numb2=rand()%max; numb3=rand()%max; casetwo(numb1,numb2,numb3,max,i); break; default:printf("ERROR\n"); } } char file1[10],file2[10],s[3]; printf("校对文件答案并生成Grade.txt文件\n"); printf("请输入练习文本：\n"); scanf("%s",file1); printf("请输入答案文本：\n"); scanf("%s",file2); int n; n=Count(file1); char exe[10000]={0}; char an[10000]={0}; GetAnswers(file1,exe); GetAnswers(file2,an); //Exercises.txt //Answers.txt Put_Judge(exe,an,n); return 0; }
5、测试运行
7、项目小结
由于没有过团队协作的经验，在这次项目中遇的了很大的困难，感觉一个人开发难度会小一点，因为不懂得如何协调好两个人的工作。通过这次项目，让我感觉到合作的重要性。
