#-*- coding:utf-8-*-
#查找列表中的一个元素,列表是排好序的;
#普通方法说
def search(list,element):
for i in range(0,len(list)):
if list[i] == element:
print("list[%d] is %d" % (i,element))
return i
print "not found!"
#二分法查找,要求列表是有序的才行
def search2(list,element):
low = 0
high = len(list)-1
while low <= high:
middle = (low+high)/2
if list[middle]>element:
high = middle-1
elif list[middle] < element:
low = middle+1
else:
print("list[%d] is %d" % (middle,element))
return 1
print "not found!"
if __name__ == "__main__":
list = [1, 3, 5, 7, 8, 9, 12, 45, 68]
element = 6
search2(list,element)