[hdu5387 Clock]时钟夹角问题

题意:给一个时刻,求时针、分钟、秒针三者之间的夹角

思路:确定参照点,求出三者的绝对夹角,然后用差来得到它们之间的夹角,钝角情况用360减去就行了。

 

#include <map>
#include <set>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <vector>
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>

using namespace std;

#define X                   first
#define Y                   second
#define pb                  push_back
#define mp                  make_pair
#define all(a)              (a).begin(), (a).end()
#define fillchar(a, x)      memset(a, x, sizeof(a))
#define copy(a, b)          memcpy(a, b, sizeof(a))

typedef long long ll;
typedef pair<int, int> pii;
typedef unsigned long long ull;

//#ifndef ONLINE_JUDGE
void RI(vector<int>&a,int n){a.resize(n);for(int i=0;i<n;i++)scanf("%d",&a[i]);}
void RI(){}void RI(int&X){scanf("%d",&X);}template<typename...R>
void RI(int&f,R&...r){RI(f);RI(r...);}void RI(int*p,int*q){int d=p<q?1:-1;
while(p!=q){scanf("%d",p);p+=d;}}void print(){cout<<endl;}template<typename T>
void print(const T t){cout<<t<<endl;}template<typename F,typename...R>
void print(const F f,const R...r){cout<<f<<", ";print(r...);}template<typename T>
void print(T*p, T*q){int d=p<q?1:-1;while(p!=q){cout<<*p<<", ";p+=d;}cout<<endl;}
//#endif
template<typename T>bool umax(T&a, const T&b){return b<=a?false:(a=b,true);}
template<typename T>bool umin(T&a, const T&b){return b>=a?false:(a=b,true);}
template<typename T>
void V2A(T a[],const vector<T>&b){for(int i=0;i<b.size();i++)a[i]=b[i];}
template<typename T>
void A2V(vector<T>&a,const T b[]){for(int i=0;i<a.size();i++)a[i]=b[i];}

const double PI = acos(-1.0);
const int INF = 1e9 + 7;
const double EPS = 1e-8;

/* -------------------------------------------------------------------------------- */

int gcd(int a, int b) {
    return b? gcd(b, a % b) : a;
}
void pri(int a, int b) {
    int g = gcd(a, b);
    a /= g;
    b /= g;
    printf("%d", a);
    if (b > 1) printf("/%d", b);
    putchar(' ');
}
int main() {
#ifndef ONLINE_JUDGE
    freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
#endif // ONLINE_JUDGE
    int T, cas = 0;
    cin >> T;
    while (T --) {
        int h, m, s;
        scanf("%d:%d:%d", &h, &m, &s);
        h = h % 12;
        int H = 3600 * h + 60 * m + s, M = 720 * m + 12 * s, S = 720 * s;
        int tot = 360 * 120;
        int HM = abs(H - M), HS = abs(H - S), MS = abs(M - S);
        umin(HM, tot - HM);
        umin(HS, tot - HS);
        umin(MS, tot - MS);
        pri(HM, 120);
        pri(HS, 120);
        pri(MS, 120);
        puts("");
    }
    return 0;
}
posted @ 2015-08-13 17:57  jklongint  阅读(377)  评论(0编辑  收藏  举报