catch 里面的代码和try catch 外面的代码执行顺序很奇怪，求大神指点

package multiShape;

public class People {
    public String className = "people class";
    public void eat() {
        System.out.println("People eat");
    }
    
    public void breath() {
        System.out.println("People breath");
    }

}

package multiShape;

public class Student extends People{
    public String className = "Student class";
    
    public void eat() {
        System.out.println("Student eat");
    }
    
    public void study() {
        System.out.println("Student study");
    }
}

 

package multiShape;

public class Test {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        People pp = new Student();
        pp.breath();
        pp.eat();
        System.out.println("---" + pp.className);
        try {
        if(1 > 0) {throw new IllegalArgumentException("throw my exception");}
        }
        catch(Exception e) {
            e.printStackTrace();
            System.out.println("======================" );
        }
        Student st = (Student)pp;
        st.breath();
        st.eat();
        st.study();
        System.out.println("---" + st.className);
    }
}

 

main 方法的执行结果：

People breath
Student eat
java.lang.IllegalArgumentException: throw my exception
---people class
======================
People breath
Student eat
Student study
---Student class
at multiShape.Test.main(Test.java:12)

 

感觉上面的这个执行结果的输出的顺序很奇怪，和我预期的结果有点不一样，我预期的结果应该是像下面这样子的：

 

People breath
Student eat
---people class
java.lang.IllegalArgumentException: throw my exception
at multiShape.Test.main(Test.java:12)
======================
People breath
Student eat
Student study
---Student class

请问为什么执行结果会是那样，而且每次执行后的输出结果顺序都会有不一样 ， 是不是因为catch 里面的代码和main 函数里面的代码是由两个线程来执行的。请大神指点。