获取url的参数
function getParams() { let url = location.search let params={} if (url.indexOf("?") != -1) { let str = url.substr(1) strs = str.split("&") for(var i = 0; i < strs.length; i ++) { params[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]) } } return params }