CCF | 小中大

问题描述

试题编号：	201903-1
试题名称：	小中大
时间限制：	1.0s
内存限制：	512.0MB
问题描述：

 

 

 

#include<bits/stdc++.h>
using namespace std;

int main()
{
    int n;
    double maxn,minn,num,midn;
    cin>>n;
    maxn = 0;
    minn = 0;
    midn = 0;
    if(n%2 == 1) {
        cin>>minn;

        for(int i = 1; i < n; i++) {
            if(i == (n-1)/2) {
                cin>>midn;
            }else if(i == n-1){
                cin>>maxn;
            } else {
                cin>>num;
            }
        }
    } else {
        cin>>minn;

        for(int i = 1; i < n; i++) {
            if(i == (n-1)/2 || i == n/2) {
                cin>>num;
                midn += num;
            }else if(i == n-1){
                cin>>maxn;
            } else {
                cin>>num;
            }
        }

        midn = midn / 2;
    }

    if(minn > maxn)
        swap(minn,maxn);

    int maxnn = (int)maxn;
    maxn - maxnn == 0 ? printf("%.0lf",maxn) : printf("%.1lf",maxn);
    int midnn = (int)midn;
    midn - midnn == 0 ? printf(" %.0lf",midn) : printf(" %.1lf",midn);
    int minnn = (int)minn;
    minn - minnn == 0 ? printf(" %.0lf",minn) : printf(" %.1lf",minnn);

    return 0;
}