一个字符串(文本)中括号匹配问题

大致思想是:

(1)定义属性,如括号以及括号的配对关系

(2)从字符串(文本)中提取括号(此处以字符串为例),从而得到一个只包含括号的字符串

(3)利用栈存储开括号,遇到闭括号就与栈顶元素进行配对(此处直接将list当做栈使用),若配对就出栈

class ParenMatch(object):
    """括号匹配问题"""
    def __init__(self, text):
        self.parens = "(){}[]"      
        self.opposite = {"(":")", "{":"}", "[":"]"}    
        self.text = text

    def generate_paren(self):
        """括号生成器,每次调用返回text里的下一括号及其位置"""
        i, text_len = 0, len(self.text)
        while True:
            while i < text_len and self.text[i] not in self.parens:
                i += 1
            if i >= text_len:
                return
            yield self.text[i], i
            i += 1

    def handle_match(self):
        """处理括号匹配问题"""
        stack = []
        for pr, i in self.generate_paren():
            if pr in self.opposite:
                stack.append(pr)           elif stack and self.opposite[stack[-1]] == pr:
                stack.pop()else:
                print("Unmatching is found at", i, "for", pr)
                return False
        return not stack

text = "[(哈哈{})]"
pm = ParenMatch(text)
print(pm.handle_match())

 

posted @ 2019-07-11 15:34  一y样  阅读(1596)  评论(0编辑  收藏  举报