树
二叉树:
1.获取树的深度
class Program { static void Main(string[] args) { Node root = new Node() { Value = 1 }; Node level21 = new Node() { Value = 2 }; Node level22 = new Node() { Value = 3 }; Node level31 = new Node() { Value = 4 }; Node level32 = new Node() { Value = 5 }; Node level33 = new Node() { Value = 6 }; Node level41 = new Node() { Value = 7 }; Node level51 = new Node() { Value = 8 }; root.LeftChild = level21; root.RightChild = level22; level21.LeftChild = level31; level22.LeftChild = level32; level22.RightChild = level33; level32.RightChild = level41; level41.LeftChild = level51; int treeDepth = GetTreeDepth(root); //int treeDepth = GetTreeDepthByLoop(root); Console.WriteLine(treeDepth); Console.ReadKey(); }
// 递归 static int GetTreeDepth(Node root) { if (root == null) return 0; int leftchilDepth = GetTreeDepth(root.LeftChild); int rightchilDepth = GetTreeDepth(root.RightChild); return leftchilDepth > rightchilDepth ? leftchilDepth + 1 : rightchilDepth + 1; } // 迭代 static int GetTreeDepthByLoop(Node root) { if (root == null) return 0; int depth = 1; List<Node> list1 = new List<Node>(); List<Node> list2 = new List<Node>(); List<Node> temp; list1.Add(root); while (true) { foreach (var node in list1) { if (node.LeftChild != null) list2.Add(node.LeftChild); if (node.RightChild != null) list2.Add(node.RightChild); } if (list2.Count > 0) depth++; else return depth; list1.Clear(); temp = list1; list1 = list2; list2 = temp; } } } #region Tree class Node { public int Value { get; set; } public Node LeftChild { get; set; } public Node RightChild { get; set; } } #endregion
2.遍历(前序,中序,后序,层序)
// 1243576 先序 static void PreOrder(Node root) { if (root == null) return; Console.Write(root.Value); PreOrder(root.LeftChild); PreOrder(root.RightChild); } // 4215736 中序 static void InOrder(Node root) { if (root == null) return; InOrder(root.LeftChild); Console.Write(root.Value); InOrder(root.RightChild); } // 4275631 后序 static void PostOrder(Node root) { if (root == null) return; PostOrder(root.LeftChild); PostOrder(root.RightChild); Console.Write(root.Value); } // 1234567 层序 static void LevelOrder(Node root) { Queue<Node> nodes = new Queue<Node>(); if (root != null) nodes.Enqueue(root); // 根节点入队 while (nodes.Any()) { var item = nodes.Dequeue(); //根节点出队 Console.Write(item.Value); if (item.LeftChild != null) nodes.Enqueue(item.LeftChild); // 左子节点入队 if (item.RightChild != null) nodes.Enqueue(item.RightChild); // 右子节点入队 } }
一般的树:
class Node { public int Value { get; set; } public List<Node> Nodes { get; set; } }
1.获取树的深度:
public List<Node> Depth { get { List<Node> path = new List<Node>(); if (Nodes != null) { foreach (Node node in Nodes) { List<Node> tmp = node.Depth; if (tmp.Count > path.Count) path = tmp; } } path.Insert(0, this); return path; } }
或者
static int FindDepth(Node n, int depth) { if (n.Nodes == null || n == null) { return depth; } int maxDepth = 0; for (int i = 0; i < n.Nodes.Count; i++) { int d = FindDepth(n.Nodes[i], depth + 1); if (d > maxDepth) { maxDepth = d; } } return maxDepth; }
或者
static int GetDepth(Node root) { if (root == null) return 0; List<Node> list1 = new List<Node>(); List<Node> list2 = new List<Node>(); List<Node> temp; list1.Add(root); int depth = 1; while (true) { foreach (Node node in list1) { if(node.Nodes!= null && node.Nodes.Any()) { foreach (Node n in node.Nodes) { list2.Add(n); } } } if (list2.Any()) depth++; else return depth; list1.Clear(); temp = list1; list1 = list2; list2 = temp; } }
2.遍历
static void GetAllNodes(Node root) { Console.WriteLine(root.Value); if (root == null || root.Nodes == null) return; foreach (Node node in root.Nodes) { GetAllNodes(node); } }
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