套汇问题 Floyd

问题：套汇。

思路：Floyd

代码：

 1 #include <cstdio>
 2 #include <cstdlib>
 3 #include <ctime>
 4 
 5 #define N 10
 6 
 7 int currencyArbitrage (double rates[][N]);
 8 
 9 int main (int argc, char **argv)
10 {
11     double R[N][N];
12     srand(time(NULL));
13     for (int i = 0; i < N; i++)
14     {
15         for (int j = 0; j < N; j++)
16         {
17             R[i][j] = ((rand() % N) + 1) * 1.0 / N;
18         }
19     }
20     R[1][2] = 1;
21     R[2][6] = 0.9;
22     R[6][1] = 1.2;
23 
24     printf("%d\n",currencyArbitrage(R));
25     return 0;
26 }
27 
28 int currencyArbitrage (double rates[][N])
29 {
30     for (int k = 0; k < N; k++)
31         for (int i = 0; i < N; i++)
32             for (int j = 0; j < N; j++)
33             {
34                 double tmp = rates[i][k] * rates[k][j];
35                 rates[i][j] = (tmp > rates[i][j]) ? tmp : rates[i][j];
36                 if ((i != j) && (rates[i][j] * rates[j][i] > 1))
37                 {
38                     return 1;
39                 }
40             }
41     return 0;
42 }

时间复杂度：O(N^3)

posted @ 2016-11-24 18:01  jiu~  阅读(991)  评论(0)  编辑  收藏  举报