随笔分类 - 二分图
二分图的判定
摘要:1 #include <cstdio> 2 #include <iostream> 3 #include <cstring> 4 #include <vector> 5 6 using namespace std; 7 8 const int max_N = 1000+2; 9 10 // 图的邻接
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Antenna Placement poj 3020
摘要:Antenna Placement Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 12104 Accepted: 5954 Description The Global Aerial Research Centre has be
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Asteroids
摘要:Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 29547 Accepted: 15807 Description Bessie wants to navigate her spaceship through a dangerou
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