剑指 Offer 25. 合并两个排序的链表(100%,91.15%)
话不多说,先上题目
输入两个递增排序的链表,合并这两个链表并使新链表中的节点仍然是递增排序的。
示例1:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
限制:
0 <= 链表长度 <= 1000
来源:力扣(LeetCode)
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode newhead = new ListNode(-1);
ListNode pre = newhead;
while(l1 != null && l2 != null) {
if(l1.val <= l2.val) {
pre.next = l1;
l1 = l1.next;
} else {
pre.next = l2;
l2 = l2.next;
}
pre = pre.next;
}
if(l1 != null) {
pre.next = l1;
}
if(l2 != null) {
pre.next = l2;
}
return newhead.next;
}
}
作者:超级鲨鱼辣椒
转载请注明原文链接:https://www.cnblogs.com/jinzlblog/p/15121393.html