mysql 函数
1.通过出生日期计算年龄 TIMESTAMPDIFF()
SELECT record.captureUrlFull, camera.cameraName, record.alarmTime, rdetail.simScore, rdetail.faceUrlFull, rdetail.facedbName, rdetail.faceName,
TIMESTAMPDIFF(
YEAR,
str_to_date(rdetail.faceBirthday, '%Y-%m-%d'),
CURDATE()
) AS age FROM `cw_alarm_record` record
2.TO_DAYS() 函数计算天数
SELECT * FROM `cw_vehicle_record` record WHERE villageCode = '320106003015001' AND plateNumber NOT IN ( SELECT plateNo FROM cw_base_vehicle ) AND plateNumber NOT IN ( SELECT plateNumber FROM cw_vehicle_discovery ) AND TO_DAYS(NOW()) - TO_DAYS(inOutTime) < 7 GROUP BY plateNumber
3.mysql 中order by 与group by的顺序 是:
select * from ** where
group by
order by
注意:group by 比order by先执行,order by不会对group by 内部进行排序,如果group by后只有一条记录,那么order by 将无效。要查出group by中最大的或最小的某一字段使用 max或min函数。
4.group by 最新一条数据(查询最新的id 连接 查询)
SELECT * FROM cw_vehicle_record r RIGHT JOIN ( SELECT MAX(id) AS id FROM cw_vehicle_record WHERE plateNumber NOT IN ( SELECT plateNumber FROM cw_vehicle_discovery ) AND plateNumber NOT IN ( SELECT plateNo FROM cw_base_vehicle ) AND villageCode = '320106003015001' AND TO_DAYS(NOW()) - TO_DAYS(inOutTime) <= 7 GROUP BY plateNumber) b ON r.id = b.id
4.DATE_SUB(CURDATE(),INTERVAL 1 DAY) DATE_FORMAT(STR_TO_DATE(DATE, '%Y-%m-%d'), '%m.%d') as date
SELECT id,num,type,DATE_FORMAT(STR_TO_DATE(DATE, '%Y-%m-%d'), '%m.%d') as date
FROM cw_capture_tendency a
WHERE
a.type = #{type}
AND a.date BETWEEN DATE_SUB(CURDATE(),INTERVAL 7 DAY) and DATE_SUB(CURDATE(),INTERVAL 1 DAY)
ORDER BY a.date
5.MAX(CAST(buildingNo AS SIGNED)) mysql 查询String数值最大的数
SELECT
MAX(CAST(buildingNo AS SIGNED)) AS buildingNo
FROM
cw_base_building
6.in find_in_set()
select id, list, name from table where 'daodao' IN ('libk', 'zyfon', 'daodao');
select id, list, name from table where find_in_set('daodao',list);
如果list是常量,则可以直接用IN, 否则要用find_in_set()函数
7.DATE_FORMAT() 函数用于以不同的格式显示日期/时间数据
select date_format( dateline, “%Y-%m-%d” ) , count( * ) from test
group by date_format( dateline , “%Y-%m-%d” )
java基础知识