js获取url参数值(转)

 

方法一：正则分析法

 

function getQueryString(name) {
    var reg =new RegExp("(^|&)"+ name +"=([^&]*)(&|$)", "i");
    var r = window.location.search.substr(1).match(reg);
    if (r !=null) return unescape(r[2]); returnnull;
    }

这样调用：

alert(GetQueryString("参数名1"));

alert(GetQueryString("参数名2"));

alert(GetQueryString("参数名3"));

方法二：

?

<span style="font-size: 16px;"><Script language="javascript">

function GetRequest() {

   var url = location.search; //获取url中"?"符后的字串

   var theRequest = new Object();

   if (url.indexOf("?") != -1) {

      var str = url.substr(1);

      strs = str.split("&");

      for(var i = 0; i < strs.length; i ++) {

         theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);

      }

   }

   return theRequest;

}

</Script></span>

这样调用：

<Script language="javascript">
var Request =new Object();
Request = GetRequest();
var 参数1,参数2,参数3,参数N;
参数1 = Request['参数1'];
参数2 = Request['参数2'];
参数3 = Request['参数3'];
参数N = Request['参数N'];
</Script>