求1000-9999之间的吸血鬼数字(穷举法Java实现)

当初学Java时做的。

代码：

public class XiXueGuiNum {
 
     /**
      * @param args
      */
     public static void main(String[] args) {
         // TODO Auto-generated method stub
         int num[] = new int[4];
         for(int i = 1000;i < 10000;++i){
             if(i%100 == 0)
                 continue;
             convertToSingleValue(i,num);
             
             for(int a = 0; a < num.length;++a)
             {
                 for(int b = 0;b < num.length;++b)
                 {
                     if(a == b)
                         continue;
                     for(int c = 0;c < num.length;++c)
                     {
                         if(c == a || c == b)
                             continue;
                         for(int d = 0;d < num.length;++d)
                         {
                             if(d == a || d == b || d == c)
                                 continue;
                             if((num[a]*10 + num[b]) * (num[c]*10 + num[d]) == i)
                                 System.out.println(i + "=" + (num[a]*10 + num[b]) + "*" + (num[c]*10 + num[d]));
                         }
                     }
                 }
             }
             
             if((num[0] * 10 + num[1]) * (num[2] * 10 + num[3]) == i)
             {
                 System.out.println(i+"=" + num[0]*10 + num[1] + "*" + num[2]*10 + num[3]);
             }
         }
     }
     public static void convertToSingleValue(int value,int[] num)
     {
         int temp = value;
         int quotient = 0;
         int remainder = 0;
         int[] times = {1000,100,10,1};
         for(int i = 0;i < num.length;++i)
         {
             quotient = temp/times[i];
             remainder = temp % times[i];
             temp = remainder;
             num[i] = quotient;
         }
     }
 }