1.委托的定义internal delegate int MyAddFunDe(int a,int b)2.匿名方法1)MyAddFunDe fun = delegate(int a,int b){ return a+b;}2)lambdaMyAddFunDe fun = (int a,int b) =>{ return a+b;}3)简洁版MyAddFunDe fun = (a,b) => a+b;