如何在数据表中存取图片 - 回复 "三足乌" 的问题
问题来源: http://www.cnblogs.com/del/archive/2009/05/28/1491186.html#1801853
准备工作:
1、在空白窗体上添加: ClientDataSet1、Button1
2、激活窗体的 OnCreate 事件、激活 Button1 的 OnClick 事件
实现代码:
准备工作:
1、在空白窗体上添加: ClientDataSet1、Button1
2、激活窗体的 OnCreate 事件、激活 Button1 的 OnClick 事件
实现代码:
unit Unit1; interface uses Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms, Dialogs, StdCtrls, DB, DBClient; type TForm1 = class(TForm) ClientDataSet1: TClientDataSet; Button1: TButton; procedure FormCreate(Sender: TObject); procedure Button1Click(Sender: TObject); end; var Form1: TForm1; implementation {$R *.dfm} const PicPath1 = 'c:\temp\test1.bmp'; {保证测试图片的存在} PicPath2 = 'c:\temp\test2.bmp'; {建立数据表并载入数据} procedure TForm1.FormCreate(Sender: TObject); begin {建表} with ClientDataSet1 do begin FieldDefs.Add('Name', ftWideString, 8); FieldDefs.Add('Age', ftInteger); FieldDefs.Add('Picture', ftGraphic); CreateDataSet; end; {添加第一条数据} ClientDataSet1.Append; ClientDataSet1['Name'] := '张三'; ClientDataSet1['Age'] := 66; TGraphicField(ClientDataSet1.FieldByName('Picture')).LoadFromFile(PicPath1); {添加第二条数据} ClientDataSet1.Append; ClientDataSet1['Name'] := '李四'; ClientDataSet1['Age'] := 16; TGraphicField(ClientDataSet1.FieldByName('Picture')).LoadFromFile(PicPath2); end; {读出指定记录中的图片数据} procedure TForm1.Button1Click(Sender: TObject); var BlobStream: TClientBlobStream; GraphicField: TGraphicField; Bitmap: TBitmap; begin {查找姓名是李四的记录} if ClientDataSet1.Locate('Name', '李四', []) then //可以把其中的李四换成张三试试 begin {读取其 Picture 字段} GraphicField := ClientDataSet1.FieldByName('Picture') as TGraphicField; {读入到 Blob 流} BlobStream := TClientBlobStream.Create(GraphicField, bmRead); {给一个 TBitmap 流是为了看看} Bitmap := TBitmap.Create; Bitmap.LoadFromStream(BlobStream); Canvas.Draw(10, 10, Bitmap); Bitmap.Free; // BlobStream.Free; end; end; end.
好的代码像粥一样,都是用时间熬出来的