HDU 3555
数位DP
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cmath> 5 #include <algorithm> 6 #define LL __int64 7 using namespace std; 8 9 LL dp[30][3]; 10 LL a[30]; 11 LL n; 12 void initial(){ 13 memset(dp,0,sizeof(dp)); 14 dp[0][0]=1LL; 15 for(int i=1;i<30;i++){ 16 dp[i][0]=dp[i-1][0]*(LL)10-dp[i-1][1]; 17 dp[i][1]=dp[i-1][0]; 18 dp[i][2]=dp[i-1][2]*(LL)10+dp[i-1][1]; 19 } 20 } 21 22 LL slove(){ 23 LL tmp=n; 24 int len=0; 25 LL ans=0; 26 while(tmp){ 27 a[++len]=tmp%(LL)10; 28 tmp/=(LL)10; 29 } 30 a[len+1]=(LL)0; 31 bool flag=false; 32 for(int i=len;i>0;i--){ 33 ans+=a[i]*dp[i-1][2]; 34 if(flag){ 35 ans+=dp[i-1][0]*a[i]; 36 } 37 if(!flag&&a[i]>4){ 38 ans+=(dp[i-1][1]); 39 } 40 if(a[i+1]==4&&a[i]==9) 41 flag=true; 42 } 43 return ans; 44 } 45 46 int main(){ 47 int T; 48 initial(); 49 scanf("%d",&T); 50 while(T--){ 51 scanf("%I64d",&n); 52 n++; 53 printf("%I64d\n",slove()); 54 } 55 return 0; 56 }
