jquery下拉分页

前段代码

<!DOCTYPE html>
<html>
<head>
<title>无限翻页测试</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="http://apps.bdimg.com/libs/jquery/2.1.4/jquery.min.js"></script>
<style type="text/css">
#spinner{
position: fixed;
top: 20px;
left: 40%;
display: block;
color: red;
font-weight: 900;
background-color: rgba(80, 80, 90, 0.22);
padding-top: 20px;
padding-bottom: 20px;
padding-left: 100px;
padding-right: 100px;
border-radius: 15px;
}
</style>
</head>
<body>
<div id="sample">
</div>
<div id="spinner">
正在加载
</div>
<script type="text/javascript">
var index = 0;
function lowEnough(){
var pageHeight = Math.max(document.body.scrollHeight,document.body.offsetHeight);
var viewportHeight = window.innerHeight ||
document.documentElement.clientHeight ||
document.body.clientHeight || 0;
var scrollHeight = window.pageYOffset ||
document.documentElement.scrollTop ||
document.body.scrollTop || 0;
return pageHeight - viewportHeight - scrollHeight < 20;
}

function doSomething(){
var htmlStr = "";
for(var i=0;i<10;i++){
htmlStr += "这是第"+index+"次加载<br>";
}
$('#sample').append(htmlStr);
index++;
pollScroll();//继续循环
$('#spinner').hide();
}

function checkScroll(){
if(!lowEnough()) return pollScroll();
$('#spinner').show();
setTimeout(doSomething,900);

}
function pollScroll(){
setTimeout(checkScroll,1000);
}
checkScroll();
</script>
</body>
</html>

posted @ 2018-09-17 13:17  li先森  阅读(2204)  评论(0编辑  收藏  举报