数组拓展——使用稀疏数组实现存取五子棋棋盘、残局
稀疏数组使用实例:
使用稀疏数组实现存取五子棋棋盘、残局:
public class ArrayDemo08 {
public static void main(String[] args) {
//1.创建一个二维数组 11*11 0:没有棋子, 1:黑棋 2:白棋
//
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始数组
System.out.println("输出原始的数组");
for (int[] ints:array1){
for (int anInt:ints){
System.out.print(anInt+"\t");
}
System.out.println();
}
//转换为稀疏数组来存
//获取有效值的个数
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array1[i][j]!=0){
sum ++;
}
}
}
System.out.println("有效值的个数"+sum);
//创建一个稀疏数组
int[][] array2 = new int[sum+1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
//遍历二维数组,将非零的值,存放稀疏数组中
int count = 0;
for (int i = 0; i < array1.length; i++) {
for (int j = 0; j < array1[1].length; j++) {
if (array1[i][j]!=0){
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}
}
}
//输出稀疏数组
System.out.println("稀疏数组!");
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0]+"\t"
+array2[i][1]+"\t"
+array2[i][2]);
}
//还原稀疏数组
System.out.println("还原稀疏数组");
//1,读取稀疏数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
//2,给其中的元素还原他的值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//3,打印原数组
for (int[] ints:array3){
for (int anInt:ints){
System.out.print(anInt+"\t");
}
System.out.println();
}
}
}
运行结果:
输出原始的数组
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
有效值的个数2
稀疏数组!
11 11 2
1 2 1
2 3 2
还原稀疏数组
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
Process finished with exit code 0