【链表】有序链表中移除重复项

 1 public class Main {
 2 
 3     public Node removeDup(Node node){
 4 
 5         if (node == null || node.next == null || node.next.next == null){
 6             return node;
 7         }
 8 
 9         Node pre = node.next;
10         Node cur = node.next.next;
11 
12         while (cur != null){
13             if (cur.data == pre.data){
14                 pre.next = cur.next;
15             }else {
16                 pre = cur;
17             }
18             cur = cur.next;
19         }
20 
21         return node;
22     }
23 
24 
25     public Node createListNodes() {
26         Node node7 = new Node(7, null);
27         Node node6 = new Node(5, node7);
28         Node node5 = new Node(5, node6);
29         Node node4 = new Node(5, node5);
30         Node node3 = new Node(3, node4);
31         Node node2 = new Node(3, node3);
32         Node node1 = new Node(1, node2);
33         Node head = new Node(0, node1); // head pointer
34 
35         return head;
36     }
37 
38     public static void main(String[] args) {
39         Main main = new Main();
40         Node node = main.removeDup(main.createListNodes());
41 
42         if (node != null) {
43             node = node.next;
44             while (node != null) {
45                 System.out.println(node.data);
46                 node = node.next;
47             }
48         }
49     }
50 }

 

posted @ 2018-12-02 10:45  Mr.van_Gogh  阅读(365)  评论(0编辑  收藏  举报