【链表】实现单链表的逆序
1 public class Main { 2 3 // 就地逆序法 4 public Node reverse(Node head) { 5 // no need to reverse 6 if (head == null || head.next == null || head.next.next == null) { 7 return head; 8 } 9 10 // pointer 11 Node pre = head; 12 Node cur = head.next; 13 Node nex = head.next.next; 14 15 while (nex != null) { 16 if (cur == head.next) // the first node's next node is null 17 { 18 cur.next = null; 19 } else { 20 cur.next = pre; 21 } 22 23 pre = cur; 24 cur = nex; 25 nex = nex.next; 26 } 27 28 cur.next = pre; 29 head.next = cur; 30 31 return head; 32 } 33 34 // 插入法 35 public Node reverse2(Node head) { 36 if (head == null || head.next == null) { 37 return head; 38 } 39 40 Node p1 = head.next; 41 42 Node p = null; 43 44 while (p1.next != null) { 45 p = p1.next; 46 p1.next = p.next; 47 p.next = head.next; 48 head.next = p; 49 } 50 51 return head; 52 } 53 54 public Node createListNodes() { 55 Node node7 = new Node(7, null); 56 Node node6 = new Node(6, node7); 57 Node node5 = new Node(5, node6); 58 Node node4 = new Node(4, node5); 59 Node node3 = new Node(3, node4); 60 Node node2 = new Node(2, node3); 61 Node node1 = new Node(1, node2); 62 Node head = new Node(0, node1); // head pointer 63 64 return head; 65 } 66 67 public static void main(String[] args) { 68 Main main = new Main(); 69 Node node = main.reverse(main.createListNodes()); 70 71 if (node == null) { 72 System.out.println("head is null"); 73 return; 74 } 75 76 while (node.next != null) { 77 System.out.println(node.next.data); 78 node = node.next; 79 } 80 81 Node node2 = main.reverse2(main.createListNodes()); 82 83 if (node2 == null) { 84 System.out.println("head is null"); 85 return; 86 } 87 88 while (node2.next != null) { 89 System.out.println(node2.next.data); 90 node2 = node2.next; 91 } 92 } 93 94 }