1 import os
2 import easygui as g
3
4 def StatisticeCodeLine(dir_name):
5 file_dict = {".py":[0,0],".c":[0,0],".cpp":[0,0],".pas":[0,0],".asm":[0,0]}
6 all_child_dir = os.walk(dir_name)
7
8 for item in all_child_dir:
9 for file in item[2]:
10 file_name,file_extension = os.path.splitext(file)
11 if file_extension in file_dict:
12 file_dict[file_extension][0] += 1
13
14 #------------------------------------------------------------
15 with open(os.path.join(item[0],file),"r",encoding='utf-8') as f:
16 for i in f:
17 file_dict[file_extension][1] += 1
18 #------------------------------------------------------------
19
20 else:
21 pass
22
23 return file_dict
24
25
26 dir_name = g.diropenbox() #这里其实是一个获取需要递归的目录，在目录里找
27 file_dict = StatisticeCodeLine(dir_name)
28 total_line_count = 0
29 detail = ""
30 for key,value in file_dict.items():
31 total_line_count += value[1]
32 detail += str(key) + "源文件" + str(value[0]) + "个,源代码" + str(value[1])+"行\n"
33
34 total_line_count = "您目前累积编写了{0}行代码，完成度{1}%\n离10万行代码还差{2}行，请继续努力！".format(total_line_count,total_line_count / 1000,100000-total_line_count)
35
36 g.textbox(total_line_count,"统计结果",text=detail) #其实你想的话这里也可以用print替代
