【Rust】树02-二叉树

环境

  • Time 2022-04-21
  • Rust 1.60.0

前言

说明

基于标准库来学习各种数据结构,并不是从头实现数据结构,未考虑实现性能。
实现了二叉树的前序、中序和后序遍历。

示例

引入模块

pub mod binary_tree;

结构定义

use super::{NodeRef, Tree};

#[derive(Default)]
pub struct BinaryTree<T> {
    root: NodeRef<T>,
}

前序遍历

fn pre_order(&self) -> Vec<&T> {
    let mut result = Vec::new();
    let mut stack = vec![&self.root];
    while let Some(node) = stack.pop() {
        if let Some(node) = node {
            stack.push(&node.right);
            stack.push(&node.left);
            result.push(&node.value);
        }
    }
    result
}

中序遍历

fn in_order(&self) -> Vec<&T> {
    let mut result = Vec::new();
    let mut stack = Vec::new();
    let mut current = &self.root;
    while current.is_some() || !stack.is_empty() {
        while let Some(node) = current {
            stack.push(current);
            current = &node.left;
        }
        current = stack.pop().unwrap();
        result.push(&current.as_ref().unwrap().value);
        current = &current.as_ref().unwrap().right;
    }
    result
}

后序遍历

fn post_order(&self) -> Vec<&T> {
    let mut stack = vec![&self.root];
    let mut result = vec![];
    while let Some(node) = stack.pop() {
        if let Some(node) = node {
            result.push(&node.value);
            stack.push(&node.left);
            stack.push(&node.right);
        }
    }
    result.reverse();
    result
}

其它方法

impl<T> BinaryTree<T> {
    pub(crate) fn root_mut(&mut self) -> &mut NodeRef<T> {
        &mut self.root
    }

    pub(crate) fn root(&self) -> &NodeRef<T> {
        &self.root
    }
}

其它未实现方法

fn insert(&mut self, _: T) {
    unimplemented!()
}

fn remove(&mut self, _: &T) -> Option<T> {
    unimplemented!()
}

fn contains(&mut self, _: &T) -> bool {
    unimplemented!()
}

总结

实现了二叉树的前序、中序和后序遍历方法,其它方法未实现。

附录

源码

use super::{NodeRef, Tree};

#[derive(Default)]
pub struct BinaryTree<T> {
    root: NodeRef<T>,
}

impl<T> Tree<T> for BinaryTree<T> {
    fn pre_order(&self) -> Vec<&T> {
        let mut result = Vec::new();
        let mut stack = vec![&self.root];
        while let Some(node) = stack.pop() {
            if let Some(node) = node {
                stack.push(&node.right);
                stack.push(&node.left);
                result.push(&node.value);
            }
        }
        result
    }

    fn in_order(&self) -> Vec<&T> {
        let mut result = Vec::new();
        let mut stack = Vec::new();
        let mut current = &self.root;
        while current.is_some() || !stack.is_empty() {
            while let Some(node) = current {
                stack.push(current);
                current = &node.left;
            }
            current = stack.pop().unwrap();
            result.push(&current.as_ref().unwrap().value);
            current = &current.as_ref().unwrap().right;
        }
        result
    }

    fn post_order(&self) -> Vec<&T> {
        let mut stack = vec![&self.root];
        let mut result = vec![];
        while let Some(node) = stack.pop() {
            if let Some(node) = node {
                result.push(&node.value);
                stack.push(&node.left);
                stack.push(&node.right);
            }
        }
        result.reverse();
        result
    }

    fn insert(&mut self, _: T) {
        unimplemented!()
    }

    fn remove(&mut self, _: &T) -> Option<T> {
        unimplemented!()
    }

    fn contains(&mut self, _: &T) -> bool {
        unimplemented!()
    }
}

impl<T> BinaryTree<T> {
    pub(crate) fn root_mut(&mut self) -> &mut NodeRef<T> {
        &mut self.root
    }

    pub(crate) fn root(&self) -> &NodeRef<T> {
        &self.root
    }
}
posted @   jiangbo4444  阅读(151)  评论(0编辑  收藏  举报
相关博文:
阅读排行:
· 阿里最新开源QwQ-32B,效果媲美deepseek-r1满血版,部署成本又又又降低了!
· 单线程的Redis速度为什么快?
· SQL Server 2025 AI相关能力初探
· AI编程工具终极对决:字节Trae VS Cursor,谁才是开发者新宠?
· 展开说说关于C#中ORM框架的用法!
历史上的今天:
2020-07-30 【JavaScript】标准内置变量 undefined
点击右上角即可分享
微信分享提示