2020年3月16日python学习笔记——详细列表解说

坚持+思考+输出

1、学习方式:查看提供视频(30分钟)+自我整理笔记(2小时)+周末视频输出

2、笔记方式按提问方式整理。

 

# name = ["like","love","love","good"]
# n2 = ["test","hebing"]
#print(dir(name))
#  'append', 'clear', 'copy', 'count', 'extend', 'index', 'insert', 'pop', 'remove', 'reverse', 'sort'

#列表的增加操作
# name.append("插入最后")   #添加到最后
# print(name)
#
# name.insert(1,"插入指定位置")
# print(name)
#
# name.extend(n2)#把n2插入到name列表里面
# print(name)
#
# name.insert(2,[1,2,3]) #列表嵌套
# print(name)


name = ["like","love","love","good"]
# n2 = ["test","hebing"]
#删除
# del name[0]  #删除指定元素
# print(name)
#
# name.pop()  #默认删除最后一个元素并返回被删除的值
# print(name)
#
# name.pop(1)#删除指定元素
# print(name)
#
# n2.clear() #直接删除
# print(n2)
name.remove("like")  #直接移出元素
print(name)

# 查操作
# name = ["like","love","love","good","like"]
# n2 = ["test","hebing"]
#
# print(name.index("love"))#返回从左开始匹配到的第一个like的索引
#
# print(name.count("like")) #返回like的个数

#切片
# name = ["like","love","love","good","like"]
# n2 = ["test","hebing"]
#
# print(name[1:7])# 切片的特性是顾头不顾尾,即start的元素会被包含,end-1是实际取出来的值
#
# print(name[1:7:2])# 步长, 允许跳着取值
#
# print(name[::-1])#通过把步长设置成负值,可达到列表返转的效果['like', 'good', 'love', 'love', 'like']

# 排序&反转
# 排序
a = [83,4,2,4,6,19,33,21]  #从小到大进行排序
# a.sort()
# print(a)

# 反转
# a.reverse()
# print(a)
# print(a[::-1])


# 循环列表
name = ["like","love","love","good","like"]
for i in name:
    print(i)

  

posted on 2020-03-16 20:48  坚持是多么伟大的事情  阅读(168)  评论(0编辑  收藏  举报