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摘要： E. Pretty Song time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output E. Pretty Song time limit 阅读全文

摘要： D. Once Again... time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given an array o 阅读全文

摘要： 题目链接：http://codeforces.com/contest/776/problem/D D. The Door Problem time limit per test 2 seconds memory limit per test 256 megabytes input standard 阅读全文

摘要： Ikki's Story IV - Panda's Trick Time Limit: 1000MS Memory Limit: 131072K Total Submissions: 9990 Accepted: 3673 Description liympanda, one of Ikki’s f 阅读全文

摘要： 题目链接：http://codeforces.com/contest/583/problem/C C. GCD Table time limit per test 2 seconds memory limit per test 256 megabytes input standard input o 阅读全文

摘要： NPY and girls Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description NPY's girlfriend blew him out!His h 阅读全文

摘要： NPY and shot Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description NPY is going to have a PE test.One o 阅读全文

摘要： The sum of gcd Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Problem Description You have an array A,the length of  阅读全文

摘要： 3289: Mato的文件管理 Description Mato同学从各路神犇以各种方式（你们懂的）收集了许多资料，这些资料一共有n份，每份有一个大小和一个编号。为了防止他人偷拷，这些资料都是加密过的，只能用Mato自己写的程序才能访问。Mato每天随机选一个区间[l,r]，他今天就看编号在此区间内 阅读全文

摘要： %%%% orz 邝斌的计算几何模板： void change(double &x0,double &y0,double a,double b,double p)//x0,y0绕a，b旋转P度{ double x = a + (x0 - a) * cos(p) - (y0 - b) * sin(p) 阅读全文