实验六
#include <fstream> #include <array> #define N 5 int main() { using namespace std; array<int, N> x{ 97, 98, 99, 100, 101 }; ofstream out; out.open("data1.dat", ios::binary); if (!out.is_open()) { cout << "fail to open data1.dat\n"; return 1; } out.write(reinterpret_cast<char*>(&x), sizeof(x)); out.close(); }
#include <iostream> #include <fstream> #include <array> #define N 5 int main() { using namespace std; array<int, N> x; ifstream in; in.open("data1.dat", ios::binary); if (!in.is_open()) { cout << "fail to open data1.dat\n"; return 1; } in.read(reinterpret_cast<char*>(&x), sizeof(x)); in.close(); for (auto i = 0; i < N; ++i) cout << x[i] << ", "; cout << "\b\b \n"; }
char类型一次只读取一个字节int 类型占四个字节,所以改为char后b会在第五个出现
#include<iostream> using namespace std; template<typename T> class Vector { private: int size; T *p; public: Vector(int n) :size{ n } { p = new T[size]; } Vector(int n,T value) :size{ n } { p = new T[size]; for (auto i = 0; i < size; i++) p[i] = value; } Vector(const Vector<T>& obj) :size{ obj.size } { p = new T[size]; for (auto i = 0; i < size; i++) p[i] = obj.p[i]; } ~Vector() { delete[] p; } T& operator[](int i) { return p[i]; } T & at(int i) { return p[i]; } int get_size()const { return size; } friend void output(Vector& obj1) { int i; for (i = 0; i < obj1.size-1; i++) cout << obj1.p[i] << " "; cout << endl; } }; void test() { using namespace std; int n; cin >> n; Vector<double> x1(n); for (auto i = 0; i < n; ++i) x1.at(i) = i * 0.7; output(x1); Vector<int> x2(n, 42); Vector<int> x3(x2); output(x2); output(x3); x2.at(0) = 77; output(x2); x3[0] = 999; output(x3); } int main() { test(); }
#include<iostream> #include<iomanip> #include<string> #include<fstream> using namespace std; void output(std::ostream & out) { char a[26][26]; cout << " "; out << " "; for (char i = 'a'; i <= 'z'; i++) { cout << setw(2) << setfill(' ') << i; out << setw(2) << setfill(' ') << i; } cout << endl; out << endl; for (int j = 0; j < 26; j++) { cout << setw(2) << setfill(' ') << j + 1; out << setw(2) << setfill(' ') << j + 1; for (int k = 0; k < 26; k++) { a[j][k] = 'A' + char((j + k + 1) % 26); cout << setw(2) << setfill(' ') << a[j][k]; out << setw(2) << setfill(' ') << a[j][k]; } out << endl; cout << endl; } } int main() { ofstream out; out.open("cipher_key.txt", ios::out); if (!out.is_open()) { cout << "fail to open cipher_ke.text" << endl; return 1; } output(out); out.close(); }