Scrapy中xpath用到中文报错

问题描述

links = sel.xpath('//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()

报错:ValueError: All strings must be XML compatible: Unicode or ASCII, no NULL bytes or control characters

 

 

解决方法

方法一:将整个xpath语句转成Unicode

links = sel.xpath(u'//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()

方法二:xpath语句用已转成Unicode的title变量

title = u"置顶"
links = sel.xpath('//i[contains(@title,"%s")]/following-sibling::a/@href' %(title)).extract()

方法三:直接用xpath中变量语法($符号加变量名)$title, 传参title即可

 
links = sel.xpath('//i[contains(@title,$title)]/following-sibling::a/@href', title="置顶").extract()
posted @ 2019-12-17 18:44  5255号蜘蛛精  阅读(358)  评论(0编辑  收藏  举报