Scrapy中xpath用到中文报错
问题描述
links = sel.xpath('//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()
报错:ValueError: All strings must be XML compatible: Unicode or ASCII, no NULL bytes or control characters
解决方法
方法一:将整个xpath语句转成Unicode
links = sel.xpath(u'//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()
方法二:xpath语句用已转成Unicode的title变量
title = u"置顶"
links = sel.xpath('//i[contains(@title,"%s")]/following-sibling::a/@href' %(title)).extract()
方法三:直接用xpath中变量语法($
符号加变量名)$title
, 传参title即可
links = sel.xpath('//i[contains(@title,$title)]/following-sibling::a/@href', title="置顶").extract()
在前进的路上,永远没有终点,只有傻逼般的坚持