Spring2.5学习2.3_如何注入基本类型

前面学习了如何注入依赖对象，现在学习一下如何注入基本类型。

PersonServiceBean.java

package xjj.service.impl;

import xjj.dao.PersonDao;
import xjj.service.PersonService;

public class PersonServiceBean implements PersonService {
	private PersonDao personDao;
	private String name;
	private Integer id;
	
	public Integer getId() {
		return id;
	}
	public void setId(Integer id) {
		this.id = id;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public PersonServiceBean() {
	}
	public void setPersonDao(PersonDao personDao) {
		this.personDao = personDao;
	}
	public PersonDao getPersonDao() {
		return personDao;
	}
	@Override
	public void save(){ 
		System.out.println("name:"+name+"\n"+"id:"+id);
		personDao.add();
    }  
}

beans.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
          <bean id="personService" class="xjj.service.impl.PersonServiceBean" >
          <property name="personDao" >
				<bean class="xjj.dao.impl.PersonDaoBean"/>          
          </property>
          <property name="name" value="xjj"></property>
          <property name="id" value="27"></property>
          </bean>
</beans>

SpringTest.java

package junit.test;

import org.junit.BeforeClass;
import org.junit.Test;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

import xjj.service.PersonService;

public class SpringTest {

	@BeforeClass
	public static void setUpBeforeClass() throws Exception {
	}

	@Test public void instanceSpring(){
		ApplicationContext ctx = new ClassPathXmlApplicationContext("beans.xml");
		PersonService personService = (PersonService)ctx.getBean("personService");
		personService.save();		
	}
}

结果：