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【LeetCode】83. Remove Duplicates from Sorted List

题目:

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

提示:

此题比较简单,注意应该将冗余的节点删除。

代码:

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode *node = head;
        while (node != NULL && node->next != NULL) {
            if (node->val != node->next->val) {
                node = node->next;
            } else {
                ListNode *tmp_node = node->next;
                node->next = node->next->next;
                delete tmp_node;
            }
        }
        return head;
    }
};
posted @ 2015-08-31 15:30  __Neo  阅读(109)  评论(0编辑  收藏  举报