[leetcode] Clone Graph
Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use#
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
https://oj.leetcode.com/problems/clone-graph/
思路:dfs来复制,用一个hashmap标记已经处理过的节点防止无限循环。
public class Solution { private HashMap<Integer, UndirectedGraphNode> map = new HashMap<Integer, UndirectedGraphNode>(); public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { map.clear(); return clone(node); } private UndirectedGraphNode clone(UndirectedGraphNode node) { if (node == null) return null; if (map.containsKey(node.label)) return map.get(node.label); UndirectedGraphNode copy = new UndirectedGraphNode(node.label); map.put(node.label, copy); for (UndirectedGraphNode each : node.neighbors) { copy.neighbors.add(clone(each)); } return copy; } public static void main(String[] args) { UndirectedGraphNode zero = new UndirectedGraphNode(0); UndirectedGraphNode one = new UndirectedGraphNode(1); UndirectedGraphNode two = new UndirectedGraphNode(2); zero.neighbors.add(one); zero.neighbors.add(two); one.neighbors.add(zero); one.neighbors.add(two); two.neighbors.add(zero); two.neighbors.add(one); two.neighbors.add(two); new Solution().cloneGraph(zero); } }
第二遍记录:注意map的运用来终止无限循环,递归复制节点执行。
/** * Definition for undirected graph. * class UndirectedGraphNode { * int label; * List<UndirectedGraphNode> neighbors; * UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); } * }; */ public class Solution { Map<Integer,UndirectedGraphNode> map = new HashMap<Integer,UndirectedGraphNode>(); public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { if(node == null) return null; if(map.containsKey(node.label)){ return map.get(node.label); } UndirectedGraphNode copy = new UndirectedGraphNode(node.label); map.put(copy.label,copy); for(UndirectedGraphNode each:node.neighbors){ copy.neighbors.add(cloneGraph(each)); } return copy; } }
参考:
http://www.cnblogs.com/lautsie/p/3356392.html
http://blog.csdn.net/kenden23/article/details/18624191
http://www.programcreek.com/2012/12/leetcode-clone-graph-java/