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By far the best solution I have seen is of O(n) time (some solutions claim to be of O(logn)turns out to be O(n)). One of the simplest ideas is to comp... 阅读全文
摘要：
Well, since theheadpointer may also be modified, we create anew_headthat points to it to facilitate the reverse process.For the example list1 -> 2 -> ... 阅读全文
摘要：
Well, since theheadpointer may also be modified, we create anew_headthat points to it to facilitate the reverse process.For the example list1 -> 2 -> ... 阅读全文
摘要：
Well, since theheadpointer may also been modified, we create anew_headthat points to it to facilitate the swapping process.For the example list1 -> 2 ... 阅读全文
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动态规划： 1 class Solution { 2 public: 3 /** 4 * @param s: A string 5 * @param p: A string includes "?" and "*" 6 * @return: A boolean... 阅读全文
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Well, so many people has tried to solve this problem using DP. And almost all of them get TLE (if you see aC++DP solution that gets accepted, please l... 阅读全文
摘要：
Well, the idea of this problem is actually very sample --- keep merging the unmerged lists in lists until there is exactly one list remained. However,... 阅读全文