摘要：
The key to this problem is to store the values in a stack. In the constructor and next, we add all the next smallest nodes into the stack. The followi... 阅读全文
摘要：
The following idea is taken from a book named 《剑指offer》 published in China.Supposen = 271, it then breaks[1, 271]into[1, 71]and[72, 271]. For[72, 271]... 阅读全文