[LeetCode] Search for a Range

The idea is to search for the left and right boundaries of target via two binary searches. Well, some tricks may be needed. Take a look at this link :-)

The code is rewritten as follows.

 1 class Solution {
 2 public:
 3     vector<int> searchRange(vector<int>& nums, int target) {
 4         int l = left(nums, target);
 5         if (l == -1) return {-1, -1};
 6         return {l, right(nums, target)};
 7     }
 8 private:
 9     int left(vector<int>& nums, int target) {
10         int n = nums.size(), l = 0, r = n - 1;
11         while (l < r) {
12             int m = l + ((r - l) >> 1);
13             if (nums[m] < target) l = m + 1;
14             else r = m;
15         }
16         return nums[l] == target ? l : -1;
17     }
18     int right(vector<int>& nums, int target) {
19         int n = nums.size(), l = 0, r = n - 1;
20         while (l < r) {
21             int m = l + ((r - l + 1) >> 1); 
22             if (nums[m] > target) r = m - 1;
23             else l = m;
24         }
25         return r;
26     }
27 };

 

posted @ 2015-08-15 16:23  jianchao-li  阅读(181)  评论(0)  编辑  收藏  举报