[LintCode] 最长公共子串
1 class Solution { 2 public: 3 /** 4 * @param A, B: Two string. 5 * @return: the length of the longest common substring. 6 */ 7 int longestCommonSubstring(string &A, string &B) { 8 // write your code here 9 int m = A.length(), n = B.length(), len = 0; 10 vector<int> cur(m + 1, 0); 11 for (int j = 1; j <= n; j++) { 12 int pre = 0; 13 for (int i = 1; i <= m; i++) { 14 int temp = cur[i]; 15 cur[i] = (A[i - 1] == B[j - 1]) ? pre + 1 : 0; 16 pre = temp; 17 len = max(len, cur[i]); 18 } 19 } 20 return len; 21 } 22 };
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