[LeetCode] Remove Duplicates from Sorted Array
Well, a medium problem. Use two pointers. One points to the curren number and the other points to the last unique number. Once duplicates occur, move the unique pointer to the right and copy the current number to it.
The code is pretty short.
1 int removeDuplicates(vector<int>& nums) { 2 while (nums.size() <= 1) return nums.size(); 3 int pos = 0; 4 for (int i = 1; i < nums.size(); i++) 5 if (nums[i] != nums[pos]) 6 nums[++pos] = nums[i]; 7 return pos + 1; 8 }
【推荐】还在用 ECharts 开发大屏?试试这款永久免费的开源 BI 工具!
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步