Given an unsorted array, find the maximum difference between the successive elements in its sorted form.

Try to solve it in linear time/space.

Return 0 if the array contains less than 2 elements.

You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.

Credits:
Special thanks to @porker2008 for adding this problem and creating all test cases.

 

 1 class Solution {
 2 public:
 3     int maximumGap(vector<int>& nums) {
 4         if(nums.size()<2) return 0;
 5         sort(nums.begin(),nums.end());    
 6         int max=0;
 7         for(int i=1;i<nums.size();i++)
 8         {
 9             if(nums[i]-nums[i-1]>max)
10                 max=nums[i]-nums[i-1];
11         }
12         return max;
13 
14     }
15 };

 

posted on 2015-05-16 18:08  黄瓜小肥皂  阅读(131)  评论(0编辑  收藏  举报