Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

 

 1 class Solution {
 2 public:
 3     uint32_t reverseBits(uint32_t n) {
 4            uint32_t bit[32]={0};
 5            uint32_t ret=0;
 6 
 7            int mid=1;
 8 
 9            for(int i=0;i<32;i++)
10            {
11                bit[i]=(n>>i)&1;
12            }
13 
14            for(int j=31;j>=0;j--)
15            {
16                ret=ret+bit[j]*mid;
17                mid=mid*2;
18            }
19 
20            return ret;
21 
22     }
23 };

 

posted on 2015-05-14 20:42  黄瓜小肥皂  阅读(149)  评论(0编辑  收藏  举报