Given an integer n, return the number of trailing zeroes in n!.

Note: Your solution should be in logarithmic time complexity.

 

 1 class Solution {
 2 public:
 3     int trailingZeroes(int n) {
 4         int res=0;
 5         while(n)
 6         {
 7             res+=n/5;
 8             n/=5;
 9         }
10 
11         return res;
12     }
13 };

 

posted on 2015-05-13 08:05  黄瓜小肥皂  阅读(148)  评论(0编辑  收藏  举报