Given a m x n grid filled with non-negative numbers,
find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
//DP,f[i][j] = min(f[i-1][j], f[i][j-1]) + a[i][j]
1 class Solution { 2 public: 3 int minPathSum(vector<vector<int> > &grid) { 4 if(grid.size() == 0 || grid[0].size() == 0){ 5 return 0; 6 } 7 8 int m = grid.size(); 9 int n = grid[0].size(); 10 11 int** dp = new int*[m]; 12 for(int i = 0; i < m; i++){ 13 dp[i] = new int[n]; 14 } 15 16 dp[0][0] = grid[0][0]; 17 18 for(int i = 1; i < m; i++){ 19 dp[i][0] = dp[i-1][0] + grid[i][0]; 20 } 21 22 for(int i = 1; i < n; i++){ 23 dp[0][i] = dp[0][i-1] + grid[0][i]; 24 } 25 26 for(int i = 1; i < m; i++){ 27 for(int j = 1; j < n; j++){ 28 dp[i][j] = (dp[i-1][j] < dp[i][j-1] ? dp[i-1][j] : dp[i][j-1]) + grid[i][j]; 29 } 30 } 31 32 return dp[m-1][n-1]; 33 } 34 };