Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.

For example, given n = 3, a solution set is:

"((()))", "(()())", "(())()", "()(())", "()()()"

 

 1 class Solution {
 2 public:
 3     void unguarded_generate(vector<string> &result,string curr,int m,int n)
 4     {
 5         if (m==0&&n==0)
 6         {
 7             result.push_back(curr);
 8         }
 9         else
10         {
11             if(m!=0)
12             {
13                 unguarded_generate(result,curr+"(",m-1,n);
14             }
15         
16             if(m<n&&n!=0)
17             {
18                 unguarded_generate(result,curr+")",m,n-1);
19             }
20         }
21     }
22  
23     vector<string> generateParenthesis(int n) 
24     {
25         vector<string> ret;
26         if(n>0)
27         {
28             unguarded_generate(ret,string(),n,n);
29         }
30         return ret;
31     }
32 };

 

posted on 2015-04-25 10:43  黄瓜小肥皂  阅读(126)  评论(0编辑  收藏  举报