Java CountingSort

Java CountingSort

 

/**
 * <html>
 * <body>
 *  <P> Copyright 1994-2018 JasonInternational </p>
 *  <p> All rights reserved.</p>
 *  <p> Created on 2018年4月10日 </p>
 *  <p> Created by Jason</p>
 *  </body>
 * </html>
 */
package cn.ucaner.algorithm.sorts;

/**
 * Counting sort is an algorithm for sorting a collection of objects according
 * to keys that are small integers; that is, it is an integer sorting algorithm.
 * It operates by counting the number of objects that have each distinct key
 * value, and using arithmetic on those counts to determine the positions of
 * each key value in the output sequence. 
 * <p>
 * Family: Counting.<br>
 * Space: An Array of length r.<br> 
 * Stable: True.<br>
 * <p>
 * Average case = O(n+r)<br>
 * Worst case = O(n+r)<br>
 * Best case = O(n+r)<br>
 * <p> 
 * NOTE: r is the range of numbers (0 to r) to be sorted.
 * <p>
 * @see <a href="https://en.wikipedia.org/wiki/Counting_sort">Counting Sort (Wikipedia)</a>
 * <br>
 * @author Justin Wetherell <phishman3579@gmail.com>
 */
public class CountingSort {

    private CountingSort() { }

    public static Integer[] sort(Integer[] unsorted) {
        int maxValue = findMax(unsorted);
        int[] counts = new int[maxValue + 1];
        updateCounts(unsorted, counts);
        populateCounts(unsorted, counts);
        return unsorted;
    }

    private static int findMax(Integer[] unsorted) {
        int max = Integer.MIN_VALUE;
        for (int i : unsorted) {
            if (i > max)
                max = i;
        }
        return max;
    }

    private static void updateCounts(Integer[] unsorted, int[] counts) {
        for (int e : unsorted)
            counts[e]++;
    }

    private static void populateCounts(Integer[] unsorted, int[] counts) {
        int index = 0;
        for (int i = 0; i < counts.length; i++) {
            int e = counts[i];
            while (e > 0) {
                unsorted[index++] = i;
                e--;
            }
        }
    }
}

　　

posted @ 2018-06-29 14:18  安以北往南  阅读(367)  评论(0)  编辑  收藏  举报