python练习_module01-1-三级菜单

以3级目录来模拟3级菜单的运作。

 

1.首先创建一个能够表明3级目录结构之间映射关系的字典，然后将其存入一个pickle文件以便调用

 1 import pickle
 2 
 3 dir_windows = ['explorer.exe']
 4 part_C = {'windows': dir_windows}
 5 
 6 dir_setup = ['rhel-7.3.iso', 'SecureCRT6.rar']
 7 dir_program = ['putty.exe', 'PhotoshopCC2016.exe']
 8 part_D = {'setup': dir_setup, 'program': dir_program}
 9 
10 dir_video = ['君の名は.mp4']
11 dir_game = ['NieR: Automata', 'Sid Meier\'s Civilization VI']
12 part_E = {'video': dir_video, 'game': dir_game}
13 
14 root = {'C': part_C, 'D': part_D, 'E': part_E}
15 
16 with open('dir.pkl','wb') as f:
17     pickle.dump(root,f)

 

2.主程序

 1 #! /usr/bin/env python3
 2 # -*- coding:utf-8 -*-
 3 # Author:Jailly
 4 
 5 '''
 6     以3级的目录结构模拟三级菜单，目录结构如下：：
 7         C
 8             windows
 9                 explorer.exe
10         D
11             setup
12                 rhel-7.3.iso
13                 SecureCRT6.rar
14             program
15                 putty.exe
16                 PhotoshopCC2016.exe
17         E
18             video
19                 君の名は.mp4
20             game
21                 NieR: Automata
22                 Sid Meier's Civilization VI 
23 '''
24 
25 import time,os,pickle
26 
27 def quit():
28     print('谢谢您的使用，正在退出系统',end = '')
29     for i in range(3):
30         time.sleep(0.5)
31         print('.',end = '')
32     time.sleep(0.5)
33     print('\n已退出！')
34     time.sleep(1)
35     exit()
36 
37 def s1(select1 = None):
38     if not select1:
39         print('欢迎进入系统，根目录下有如下分区：%s' % ('、'.join(sorted(root.keys()))))
40         select1 = input('请选择您想要执行的操作：(“[分区名]”：进入分区；“q”：退出)：')
41 
42     if select1 in root.keys():
43         s2(select1)
44     elif select1 == 'q':
45         quit()
46     else:
47         select1 = input('您的输入不正确，请重新输入：')
48         s1(select1)
49 
50 def s2(select1,select2 = None):
51 
52     if not select2:
53         print('当前路径为%s，有如下目录：%s' % (select1,'、'.join(sorted(root[select1].keys()))))
54         select2 = input('请选择您要执行的操作(“[目录名]”：进入目录；"b":返回上一级；“q”：退出)：')
55 
56     if select2 in root[select1].keys():
57         s3(select1,select2)
58     elif select2 == 'b':
59         s1()
60     elif select2 == 'q':
61         quit()
62     else:
63         select2 = input('您的输入不正确，请重新输入：')
64         s2(select1,select2)
65 
66 def s3(select1,select2,select3 = None):
67 
68     if not select3:
69         print('当前路径为%s，有如下文件：%s' % (os.path.join(select1,select2),'、'.join(sorted(root[select1][select2]))))
70         select3 = input('请选择您要执行的操作(“b”：返回上一级；“q”：退出)：')
71 
72     if select3 == 'b':
73         s2(select1)
74     elif select3 == 'q':
75         quit()
76     else:
77         select3 = input('您的输入不正确，请重新输入(“b”：返回上一级，“q”：退出)：')
78         s3(select1,select2)
79 
80 if __name__ == '__main__':
81 
82     with open('dir.pkl','br') as f:
83         root = pickle.load(f)
84 
85     s1()

 

或者使用循环的方式来实现：http://www.cnblogs.com/jailly/p/6710179.html

posted @ 2017-04-14 16:40  jailly  阅读(422)  评论(0)  编辑  收藏  举报