lua table序列化和反序列化

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function serialize(obj)
    local lua = ""
    local t = type(obj)
    if t == "number" then
        lua = lua .. obj
    elseif t == "boolean" then
        lua = lua .. tostring(obj)
    elseif t == "string" then
        lua = lua .. string.format("%q", obj)
    elseif t == "table" then
        lua = lua .. "{\n"
    for k, v in pairs(obj) do
        lua = lua .. "[" .. serialize(k) .. "]=" .. serialize(v) .. ",\n"
    end
    local metatable = getmetatable(obj)
        if metatable ~= nil and type(metatable.__index) == "table" then
        for k, v in pairs(metatable.__index) do
            lua = lua .. "[" .. serialize(k) .. "]=" .. serialize(v) .. ",\n"
        end
    end
        lua = lua .. "}"
    elseif t == "nil" then
        return nil
    else
        error("can not serialize a " .. t .. " type.")
    end
    return lua
end

function unserialize(lua)
    local t = type(lua)
    if t == "nil" or lua == "" then
        return nil
    elseif t == "number" or t == "string" or t == "boolean" then
        lua = tostring(lua)
    else
        error("can not unserialize a " .. t .. " type.")
    end
    lua = "return " .. lua
    local func = loadstring(lua)
    if func == nil then
        return nil
    end
    return func()
end

-- 测试代码如下
data = {["a"] = "a", ["b"] = "b", [1] = 1, [2] = 2, ["t"] = {1, 2, 3}}
local sz = serialize(data)
print(sz)
print("---------")
print(serialize(unserialize(sz)))
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测试输出如下:

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{
["a"]="a",
[2]=2,
["b"]="b",
[1]=1,
["t"]={
[1]=1,
[2]=2,
[3]=3,
},
}
---------
{
["a"]="a",
[2]=2,
["b"]="b",
[1]=1,
["t"]={
[1]=1,
[2]=2,
[3]=3,
},
}
复制代码

 

posted @   云轩奕鹤  阅读(4747)  评论(0编辑  收藏  举报
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