class Solution(object): def fizzBuzz(self, n): a = [] i = 1 while(i <= n): if(i%15 == 0): a.append("FizzBuzz") elifleetcode day_01

412. Fizz Buzz

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

  自己答案:

class Solution(object):
         def fizzBuzz(self, n):
      a = []
      i = 1
      while(i <= n):
        if(i%15 == 0):
          a.append("FizzBuzz")

        elif(i%3 == 0):
          a.append("Fizz")
        elif(i%5 == 0):
          a.append("Buzz")

        else:
          a.append(str(i))
        i = i + 1
      return a

  经典答案:

1.

class Solution(object):
    def fizzBuzz(self, n):
       return [str(i) if (i%3!=0 and i%5!=0) else (('Fizz'*(i%3==0)) + ('Buzz'*(i%5==0))) for i in range(1,n+1)]

2.

class Solution(object):
    def fizzBuzz(self, n):
return["Fizz"*(not i%3) + "Buzz"*(not i %5) or str(i) for i in range(1,n+1)]

自己的答案没有考虑到列表生成式,没有发挥出Python特点:优雅、简介

列表生成式资料:

http://www.liaoxuefeng.com/wiki/001374738125095c955c1e6d8bb493182103fac9270762a000/00138681963899940a998c0ace64bb5ad45d1b56b103c48000

 

posted @ 2016-11-16 17:46  Chaz_Sun  阅读(1002)  评论(0编辑  收藏  举报